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Course homeModule I-08 · Recommended before: Before empirical formulas and hydrates
Percent composition and chemical formulas
Formula composition connects component masses to a whole sample. Use mole ratios rather than mass ratios to determine empirical formulas.
Learn the method
mass percent = (mass of element/mass of compound) × 100
- Convert element masses into moles.
- Divide each mole amount by the smallest.
- Multiply ratios to obtain small whole numbers when needed.
- Verify the final formula and compute percent composition.
Common mistake: Never determine subscripts directly from grams; convert masses to moles first.
Worked example
Problem: A compound contains 12.01 g C and 32.00 g O. Determine its empirical formula.
Step-by-step solution: 12.01 g C ÷ 12.01 g/mol = 1.00 mol C; 32.00 g O ÷ 16.00 g/mol = 2.00 mol O. Empirical formula CO₂.
Check the units and whether the answer is reasonable before continuing.
More applications of this mathematics
Try each extension before expanding its solution.
Empirical formulas from masses
12.01 g carbon and 32.00 g oxygen correspond to 1.00 mol C and 2.00 mol O, producing CO₂.
Hydrates
If 2.00 g anhydrous salt corresponds to 0.0200 mol formula units, and 1.80 g water is lost (0.100 mol), hydrate ratio water:salt = 5:1.
Molecular formula multiplier
An empirical formula CH₂O has empirical formula mass 30.03 g/mol. If the molar mass is 180.18 g/mol, multiplier=6 and formula=C₆H₁₂O₆.
Independent practice — five questions
Suggested mastery threshold: four out of five. Incorrect answers display a worked explanation after submission.
Supporting reference
OpenStax Chemistry 2e / NIST — reference for this subject. This lesson’s wording, examples and questions are original.
IntoChemistry original instructional content, 2026. Formative feedback is not an official course grade. Sources are linked for independent reading. Accessibility testing with your institution and assistive technology is still recommended.