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Course homeModule II-03 · Recommended before: Before integrated rate laws
Natural logarithms and exponential models
Natural logarithms undo exponential functions with base e. These operations solve kinetic equations for time or concentrations.
Learn the method
Aₜ = A₀ e^(−kt)
- Identify an equation containing e^(−kt).
- Divide to isolate the exponential term.
- Take ln of both sides.
- Solve for time or rate constant.
- Verify that decay produces a smaller amount.
Common mistake: ln(2) is approximately 0.693, not 0.301 (which is log₁₀2).
Worked example
Problem: Find time when a first-order process decreases to half its original amount with k = 0.100 min⁻¹.
Step-by-step solution: t = ln(2)/k = 0.693147/0.100 = 6.93 min.
Check the units and whether the answer is reasonable before continuing.
More applications of this mathematics
Try each extension before expanding its solution.
Time from first-order concentration
For [A]₀ = 0.100 M, [A]ₜ = 0.0250 M and k = 0.200 min⁻¹, t = ln(4)/0.200 = 6.93 min.
Log base matters
ln(2)=0.6931, whereas log₁₀(2)=0.3010. They are not interchangeable without the correct conversion factor.
Independent practice — five questions
Suggested mastery threshold: four out of five. Incorrect answers display a worked explanation after submission.
Supporting reference
OpenStax Chemistry 2e / NIST — reference for this subject. This lesson’s wording, examples and questions are original.
Applied practice: Natural logarithms and exponential change
These ungraded questions extend the scored five-question check. Work each problem before opening its solution; progress records are not changed.
Challenge 1. A first-order reaction starts at [A]₀ = 0.200 M with k = 0.100 min⁻¹. Find [A] after 10.0 min.
Show worked solution for challenge 1
[A] = [A]₀ e⁻ᵏᵗ = 0.200e⁻¹·⁰⁰ = 0.0736 M.
Challenge 2. Compute ln(5.00) and log₁₀(5.00). Why do they differ?
Show worked solution for challenge 2
ln(5.00) ≈ 1.609; log₁₀(5.00) ≈ 0.6990. Natural logs use base e; common logs use base 10. Match the equation’s required base.
IntoChemistry original instructional content, 2026. Formative feedback is not an official course grade. Sources are linked for independent reading. Accessibility testing with your institution and assistive technology is still recommended.