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Course homeModule II-15 · Recommended before: Before electrolysis, nuclear chemistry and lab reports
Electrolysis, nuclear decay and data analysis
Quantitative electricity relates current to charge and electron moles. Nuclear decay uses exponential half-life; both rely on careful unit tracking.
Learn the method
Q = It; mol electrons = Q/F; remaining = initial×(1/2)^(t/t₁/₂)
- For electrolysis compute charge Q = I×t in coulombs.
- Divide by Faraday’s constant to find electron moles.
- Use stoichiometric electron-to-product ratios.
- For nuclear decay use fractions of one-half for each half-life.
- Report units and measurement uncertainty clearly.
Common mistake: For electrolysis, convert minutes to seconds before multiplying by amperes.
Worked example
Problem: A sample has 80.0 mg of a radioisotope with half-life 5 days. How much remains after 15 days?
Step-by-step solution: Three half-lives: 80.0 × (1/2)³ = 10.0 mg.
Check the units and whether the answer is reasonable before continuing.
More applications of this mathematics
Try each extension before expanding its solution.
Faraday mass calculation
For Cu²⁺+2e⁻→Cu, 1.00 A for 1930 s supplies 1930 C ≈0.0200 mol electrons, enough for 0.0100 mol Cu or about 0.636 g copper.
Decay law and laboratory statistics
Three half-lives leave (1/2)³ = 12.5% of the original amount. In lab data analysis, state whether reported variation is sample standard deviation, standard error, or instrument uncertainty.
Mass defect and binding energy
A nuclear mass defect of 1.00×10⁻³⁰ kg corresponds to E=Δmc²≈8.99×10⁻¹⁴ J using c≈2.998×10⁸ m/s.
Precision in lab reports
For three measurements 1.00, 1.10, 0.90 g, the mean is 1.00 g; sample standard deviation=0.10 g and relative standard deviation=10%.
Independent practice — five questions
Suggested mastery threshold: four out of five. Incorrect answers display a worked explanation after submission.
Supporting reference
OpenStax Chemistry 2e / NIST — reference for this subject. This lesson’s wording, examples and questions are original. Electrolysis reference: https://openstax.org/books/chemistry-2e/pages/17-introduction
Applied practice: Electrolysis mass and nuclear half-life
These additional, ungraded problems cover skills beyond the scored five-question check above. Try each before expanding its solution. Your existing score and progress records are unchanged.
Challenge 1. An aqueous Cu²⁺ solution is electrolyzed at 2.00 A for 30.0 min, producing copper. Find the deposited mass (F = 96,485 C/mol e⁻; Cu = 63.55 g/mol).
Show worked solution for challenge 1
Q = It = (2.00 A)(1,800 s) = 3,600 C. Cu²⁺ + 2e⁻ → Cu; m = (3,600 C)(63.55 g/mol) / (2 × 96,485 C/mol) = 1.19 g Cu.
Challenge 2. An isotope has a half-life of 8.0 days. A 64 mg sample is measured after 24 days. How much remains?
Show worked solution for challenge 2
24/8.0 = 3 half-lives; remaining = 64 mg × (1/2)³ = 8.0 mg.
IntoChemistry original instructional content, 2026. Formative feedback is not an official course grade. Sources are linked for independent reading. Accessibility testing with your institution and assistive technology is still recommended.