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Course homeModule II-10 · Recommended before: Before acid-base calculations
pH, pOH and weak-acid equilibrium
Acid-base equilibria require logarithms and careful concentration balances. For weak acids, the small-x approximation is valid only if checked.
Learn the method
pH = −log₁₀[H₃O⁺]; at 25 °C, pH + pOH = 14.00
- Identify [H₃O⁺] or [OH⁻].
- Use pH = −log₁₀[H₃O⁺] or pOH = −log₁₀[OH⁻].
- At 25 °C, pH+pOH = 14.00 under dilute aqueous conditions.
- If using K_a or K_b, solve the equilibrium expression.
- Check reasonableness.
Common mistake: pH+pOH = 14.00 is a 25 °C relationship and should not be assumed universally.
Worked example
Problem: At 25 °C, an aqueous solution has [OH⁻] = 1.0×10⁻⁴ M. Calculate pH.
Step-by-step solution: pOH = 4.00; pH = 14.00−4.00 = 10.00.
Check the units and whether the answer is reasonable before continuing.
More applications of this mathematics
Try each extension before expanding its solution.
Weak-acid estimate
For a weak HA with Ka = 1.0×10⁻⁵ and initial concentration 0.100 M, x≈√(KaC)=1.0×10⁻³ M, giving pH≈3.00; x/C≈1%, so the approximation is reasonable.
Temperature dependence
At 25 °C, pH+pOH=14.00 is useful for dilute aqueous systems. For other temperatures, calculate pKw from Kw at that temperature.
Polyprotic acid steps
For a diprotic acid, Ka₁ and Ka₂ describe separate ionizations. When Ka₁≫Ka₂, the first dissociation often dominates [H₃O⁺], but the second step may matter for speciation.
Independent practice — five questions
Suggested mastery threshold: four out of five. Incorrect answers display a worked explanation after submission.
Supporting reference
OpenStax Chemistry 2e / NIST — reference for this subject. This lesson’s wording, examples and questions are original.
Applied practice: Weak-acid approximations and pH
These ungraded questions extend the scored five-question check. Work each problem before opening its solution; progress records are not changed.
Challenge 1. A monoprotic weak acid has initial concentration 0.100 M and Kₐ = 1.8 × 10⁻⁵. Estimate pH and check the small-x assumption.
Show worked solution for challenge 1
Approximate [H₃O⁺] = √(KₐC) = √(1.8 × 10⁻⁶) = 1.34 × 10⁻³ M. pH ≈ 2.87. Ionization is 1.34% of 0.100 M, below the common 5% guideline.
Challenge 2. Find pH when [H₃O⁺] = 2.00 × 10⁻³ M.
Show worked solution for challenge 2
pH = −log₁₀(2.00 × 10⁻³) = 2.699 (three decimal places for three significant figures in concentration).
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